WebMolar mass of NO2/N2O4 mixture = Vapor density * 2 = 76.6 g mol^(-1) Let the percentage of NO2 gas be X, the percentage of N2O4 gas be 1-X X(molar mass of NO2 gas) + (1-X)(molar mass of N2O4) = 76.6 X(46) + (1-X)(92) = 76.6 X = 33.48% Mass of NO2 in 100g of mixture = 33.48g Number of moles of NO2 gas = 33.48/46 = 0.728 mol WebOne mole of N2O4 at 300K is kept in a closed container under 1atm pressure. It is heated to 600K when 20% by mass of N2O4 decomposes to NO2 (g) . The resultant pressure is: A.1.2atm B.2.4atm C.2atm D.1atm Advertisement Satyanath8475 is waiting for your help. Add your answer and earn points. Answer
A mixture of \\ [N {O_2}\\] and \\ [ {N_2} {O_4}\\] has a vapour ...
Web04. apr 2024. · N 2 O 4 can be calculated as: Molar mass = 2 (Vapour density) = 2 (38.3) = 76.6 Ow, let the total number of moles of gases present in the mixture be 1. Then, let us consider the number of moles of N O 2 to be ‘n’. hence, the number of moles of N 2 O 4 is ( … WebOne mole of N 2O 4 at 300 K is kept in a closed container under one atmosphere. It is heated to 600K when 20% by mass of N 2O 4 decomposes to NO 2 ( g ) . The resultant … canning chow chow with cabbage
At 27°C ,1atm, 20% of N2O4 dissociated into NO2. Determine the …
WebTwo liquids A and B form an ideal solution. At 300 K, the vapour pressure of a solution containing 1 mole of A and 3 mole of B is 550 mm of Hg. At the same temperature, if one more mole of B is added to this solution, the vapour pressure of the solution increases by 10 mm of Hg. Determine the vapour pressure of A and B in their pure states. Web09. maj 2024. · A reaction occurs in a mixture of 19.3 g Ca (OH) 2, 21.7 g CH 3 COOH, 41.2 g Ca (CH 3 COO) 2, and 70.1 g H 2 O. In what direction will the reaction proced? How many grams of each will be present at equilibrium? 41 Given, the thermal decomposition of CaCO 3 (g) → CaO (g) + CO 2 (g); Kc=4.84 @300K WebOne mole of N 2O4 gas at 300 K is kept in a closed container at 1 atm. It is heated to 600 K when 20 percent by mass of N 2O4 decomposes to N O2(g). The resultant pressure in the container would be 3118 49 Chemical Kinetics Report Error A 1.2 atm B 2.4 atm C 2 .0 atm D 1.0 atm Solution: N 2O4 − −−−− > 2N O2 I nitial1mol Ateqm. (1−0.2)mol 0.4mol canning chokecherry juice